sửa chữa máy hàn sử dụng công nghệ inverter

Bạn đang xem bản rút gọn của tài liệu. Xem và tải ngay bản đầy đủ của tài liệu tại đây (17.1 MB, 106 trang )

;

·.

I’

‘fRlJ1\JG TAM· STJP�-·rv11\Y.H1\N INVERTER.
A

,_

�

.

‘ .

;”l1,.

TAI-LIEU’
.
A

‘

.

.

,

.

•a;..r.,,,”.·

· .·. · BUA CHUA MAY HAN sU’,ouNG
.
CONG NGHE• INVERTER
MOFET � IGBT – Cd
.

.

.

\

A

.

‘

.

.

A

• ��! •

•1

,,

.

‘rHANG 10-2017
1′

..

‘

· · .·

\

.

\

.

;

PHAN I : MAY HAN DI¥N TU HAN QUE, TIG; CUT PLASMA
CH�Y MOSFET.
NGUYEN LY CO BAN
-Mayhan di�n tu sir d1;mg cong ngh� inverter. Cong ngh� inverter sir d1=1ng cong sudt d8

diSu chinh dong t�i ngo ra, khac hoan toah so v6i cong ngh� SU d1=1ng bi8n ap (Su d1=1ng.
trgc ti8p t�i CUQn thu cdp CUa bi8n ap).
.

‘

‘

-Thanh phfrn cua mayhan bao g6m: -Phfrn ngu6n tu 220VAC t�o ra di�n ap 31 OVDC,
duqc cung cdp cho dan cong su&t Mosfet, clan nayduqc dong ma ph1=1 thudiSu khi8n xung, tin hi�u sau cong su�t duqc dua vao bi8n ap lgc d8 t�o ra muc di�n. ap
sau cudi�n ap 1 chiSu va duqc gful· trgc ti8p vao 2 CQC han.
· -Mayhan di�n tir sir d\lflg 3 bo m�ch-: Bo m�ch ngu6n, Bo m�ch cong sufit va Bo lgc.
‘

.

‘

cAc BUOC KIEM TRA ca BAN

-Bmrc 1: Ki@m tra phich cim-(Day dful, phich cim, tr6 m6i, …).
+Chinh d6ng h6 vS thang do xl O (Thang do di�n tr6).
+Dua 2 dfru .que do vao 2 chan cua phich cim.
+B�t cong tic va quan sat d6ng h6 th&y kim len l chut, d6ng nghTa phfrn nayda d�t.
+NSu kim’ khong len: Ki8mtra day dful bi dut haykhong, cong tic ngu6n c6 hong khong,
NTC ho�c PTC c6 ch8t khong, duong m�ch bi dut haykhong.
+NSu kim len h8t: Ki8m tra Di6t cfru.

-Bmrc 2: Ki8m tra 2 dfru CQC han.
+Chinh d6ng h6 vS thang do xl O (Thang do di�ntr6)

‘t
Page 1

+Dua2 ddu·quedo vao 2 chan cua CQC han va dao chiSu quedo
+Kim d6ng h6 len 1 chiSu ho�c len 2 chiSu hoa11 toan khac nhau thi phdn nay dad�t (Dan
Di& chinh luu khong bi·ch�p) .
+NSu kim len 2 chiSu nhu nhau cdn ki8m tra xem c6 linh ki�n bi chay nao khong (T�i bo
1\rc),._cac CQC bit 96 bi ch�m VO hay khong, dan Di6t D92-02.
-Bmrc3: Ki�m tra Cong.suit
+Chinhd6ng h6 vS thang �o xl O (Thangdo di�n tr&).

+Ki/in tra 2 chlin D va Scua so: .
..

.

• Que do·dua vao ·Chan D, que-·dendua vao chan S: Kimd6ng h6 Jen; Queden dua
vao chan D,. quedodua vao chan S: Kim d6ng h6 khong lenk8t lu� DS cua so
khong ch8t.
.
. .
• Cdn ki8m tra.DS cua cac so (So duqc chia lam 4 nhanh, do v�y ch(mg ta cdn ki8m
.
tra h8t ca 4 nhanh).

+Ki€m.’tra 2 chlin G va S cua. so:

• Quedodua vao chan S, que den dua vao chan G : Kim len, Queden dua vao chan
S, quedodua vao chan G kim len l chut ho�c khong len, k8t lu�n GS cua so khong
chst.
• M�o: C6 th8 dotrvc ti8p t?i bo .chia xung. Bo chia iung chia thanh 4 nhanh, ki8m
tra tung nhanh m9t (Que do ben �goai, queden bemtrong thi kimd6ng h6len.
Nguqc l�i kim le;n 1 · chut ho�c khong len, K8t lu�n nhanhd6 d�t. Nhanh nao ma
kitµ len h8t, ho�c khong len chung ta cdn ki8m tra so va nhanh cua ho chia xung.

-1
Page 2

Page3

Bo 11gu6n

Page4

l_

Bolµc

C\

Page5

f’AN220V

SWllCM

…

Su ttJ khai mtiy !ig, cut va cac rite ciim

/1

Page6

I. Mica NGUON
Mayhan que, tig, cut cfin c6 cac di�n ap sau:
-Di�n ap 220 VAC cdp dS,nuoi qu�t, t�i di�n ap 310 VDC b�ng each chinh luu d.u va tv l9c
nguon.
.

.

-Di�n ap 310 VDC cfip dS t�o nguf>n 24 VDC va cfip di�n tnJC tiSp cho So.
-Di�n ap 24 Vol d8 dong ma Role nguf>n, cdp nguf>n cho IRF va cdp nguf>n cho 7812 va 7805.
-Di�n ap 12 Vol dugc su dvng cho m�cl diSu khiSn vii t�o xuµg. :·
i

-Di�n ap 7 Vol cfip cho chiSt ap
-Di�n ap 5vol dugc cdp dS nuoi man hinh led hiSn: thi dong.

Page 7

.

1.1 Mach tao
.• 310VDC
.

JU.:.
ff-�1-1ik�
;!,1V ..�.:.V:-:.tlJ\:’M.’.
XI

‘.!20V/50Hl

i>I

)NM!H

IV!,
r

>I-=

i-,:,
tN,:t’.f)-1

c� •,.-.,

+

UX5

!i

ll);i
C;-!5l1!2\’.,

[
M�ch nguyen ly ngu6n 310VAC
Dien ap 220 VAC;
V6i mfch ngu6n sfr d\mg 1 ciu diot: ·1 chan 220″‘ se di tr\Jc tiSp vao 1 chan xoay chiSu, 1 chan
con l�i se di qu� nhanh Ptc ho�c Ntc ds· cftp vao chan xoay chiSu con l�i cua m�ch c§.u.
V6i mfch ngu6n sir d\lng 2 diot ciu: 1 chan 220″‘ se di tr\JC ti6p vao 2 chan xoay chiSu cua 1
diot c§.u, chan cori l�i se di qua nhanh ptc ho�c ntc dS cftp cho 2 chan xoay chiSu cua diot c§.u
con l�i.
– Sau khi 220 xoay chiSu duqc cdp vao diot cdu, se t�o ra duqc di�n ap 1 chiSu (Xem l�i (mg
· dvng cua diot du), di�n ap 1 chiSu nay duqc l9c qua tv ngu6n t�o ph�ng d� t�o ra di�n ap
31 0VDC Sau d6 se c6 1 m�ch ngu6n ti r 31 0VDC t�o ra 24VDC dS cftp cho role ngu6n dS d6�g
tr\Jc tiSp 1 chan 220 VAC (nhanh vira di qua ptc ho�c ntc) dS duy tri (ptc ho�c ntc chi mo thai
diSm d§.u sau khi ddn di�n qua n6 se n6ng len va ng�t khong cho di�n di qua va da duqc duy tri
b�ng tiSp dism. cua role ngubn).

.9

Page 8

cAu E>IOT

NGUON

24VDC

NGUON

310VDC

TV NGUON
470uF/400V

Bo ngu6n may han que

Ma vit
Caoap
2.5s/5s

Bo ngu6n may tig/que
Page9

Cacpan benhthuong xay ra v6i vimg ngu6n 310 VDC:
Pan 1: Khong co ilijn_apvao 220AC(Qugt khong 9uay).
.

.

.

-KiSm tra day ddn, kiSm tra cong tic, kiSm tra nhanh ntc (g6m ntc; cfiu chi.. J bing each do
thong day va ti€p di€in corig tic, do ntc thong.
-KiSm tra qu�t (thir cim tqrc ti€p 2 ch.an qu�t vao ngu6n 200VAC).

Pan 2: Co 220AC ( q’u{lt co quay) nhung chua co 310VDC.
-Rut ric 310v vao congsuftt dS tach tai cua ngu6n 310v.
-KiSm tra chan cua diot cfiu, ric cdm.
-KiSm tra cfiu diot.
-KiSm tra duong m�ch (th�ong.bi dm)�.
Pan 3: Cdm nguJn co tiing nJ to; nhay Attomat.
-KiSm tra diot cfiu, tv ngu6n, cong sud t
Pan 4: Co nguJn 31OVDC nhung ch{ly i luc thi bi ngdt. .
-KiSm tra ngu6n 24VDC.
.:.KiSm tra dien ap cdp vao CUQn hut cua role.24VoL
-KiSm tra ti€p diSm cua role ngu6ri.
Mfo stra vimg ;ngu6n: ·
‘

‘

-KiSm tra nhanh: Dot�i 2 chanphich cim (thang do xlO om b�t cong tic thi kim. len, tit cOng
tic thikim khong len. (day, cong tic, ntcs6ng).
-KiSm tra diot cdu .
-Quansat tv ngu6ri va cac ric.
Page 10

1.2 Difn ap 24 VOL
-0UQ’C l�y di�n ap tu 31 OVDC (sau m�ch chinh luu)
-Sir d\mg ngu6n xung d€ t�o ra 24VDC

Vt
:mw

0105
C105
C103

!!)lffiWI,/

.. R210
.S10l”ll#

R213
5100:

!HOO
C10

zr;1-102
IN’J/

R:21′.¼t
!iJ ,;t

R207

0108
tN41�

109

�
r

Page 11

‘i

Linh ki�n str d1_mg:

-BiSn ap xung 200:6
-So cong sudt (K3878, K2611, K4107 …)
-Tram6i SIOK
-T\l va diot d�p xung cho So.
-M�ch t�o xung va xu ly h6i tiSp
Cac bU’&c ki�m tra va sfra mJch ngu6n 24Vol:
-KiSm tra c6 31OVDC
-Tach tai vao 7812 va IRF
Page 12

-Kiem tra So, tra m6i, d�p xung
-Kiem tra vimg t�o xung va XU ly h6i tiSp

-Kiem tra biSn ap xung
1.3 Mfch nguon 12 Vol
‘::i\_

.1 N’4002

LM 7812 IC with heat sink

+.
24VDC

fl

12VDC
1.5A

. -KiSm tra ngu6n vao 24 Vol
-KiSm tra chdn ra t�i 7812, dS y trucrnghgp 7812 bj,n6ng nen’kiem tra tai bi ch�p (Thucrng thi
IC cung n6ng theo, dn thay IC m6’i)
-Ngu6n 12 Vol cfip cho IC so sanh, IC dao d9ng, Transistor 8050…
Page 13

Yung khoanh tron la IC 7812, chan 1 la ngu6n cdp 24v, chan 2 la mass, chan 3 la ngo ra 12v.
Luu y: Khi sua chung ta dn d� y t6.i ngu6n cdp, ic t�o di�n ap chudn va tai phia sau ngu6n cdp
. cts dua ra nhung phan doan, m9t s6 truang hqp dn thay thu ct� rut kinh nghi�m khi sua chua.
1.4 M,ch n�uAn ‘5 Vol’
-Ki�m tra ngu6n cdp, duqc SU dl)ng tu ngu6n 24v ghep qua di�n tra 22 om/3 w.
· · -KiSm tra led hiSrt thi dong va kiSm. tra 7805.

Page 14

.

.

II.MACH TAO XUNG

;’INl.l
.

–

,._i_,_’

f’1N t,;5′

-{i�- ‘.1.rJ/’
1.

(o/.V2

RU
lf.

�.x.-·

flNl\

.

‘

f-*-+t.:::>-‘!-1–£

1

f1 �,i

Sa d6 nguyen ‘ly m�ch bo d\1’11g 3525
2.1 Nguyen ly hoJt dqng
-M�ch t�o xung duqc xu ly b�ng IC t�o xung Ka3525 v6i chan ngu6n cdp la chan 15 va· chan
12 (Nhu hinh), chan kich dS t�o duqc xung la chan s6 8, chan 2 va chan 9 la chan nh�n tin
hi�u tu m�ch xu ly kich. dong va phan h6i dong vs d8 cho phep xung ma vai ddua tin hi�u xung ra de dong macho cong sudt (So), xung ra duqc xudt phat tµ chan 11 va
14 cua IC. Tin hi�u xung nay dugc xu ly qua vung m�ch 8050 va 8550, sau do tin hi�u dugc
dua qua IRF .z24 va 9z24, tin hi�u sau IRF se duqc gui t6i m�ch chia xung 16: 8 d� cdp cho
so. Bo xung 16:8 ho�t d-M�chxu ly chinh dong va bao dong vs tu shunt se dugc xu ly qua ic CA3140 (le _khuSch
d�i thu�t toan).
-M�ch bao v� qua dong se nh�n tin hi�u tu bi�n ap bao v� 300:1 dugc bao tin hi�u di�n ap vS
linh ki�n bao v� fhyrist�r;’bc Rul0v0… )di\ ng�txung vit d6ng thai bao 16i qua tai 0.C (over
_
circuit).
�/
_
:.

Page 15

Tr6t1K

Bo m�ch 3525

�Tieu chuin:

•,.

·,1:(,

.;.

+IC3525
Chan 15
12 Vol

Chan 12
0 Vol

Chan8. Chan 11
·5 Vol
5 Vol

Chan 14
5Vol

+Chan G t�i IRF: 5vol – 20vol- 5vol – 20vol (bao g6m 4 chan IRFZ24 va IRF9Z24)
+Di�n ap t�i tai nhi�t cac IRF: 13 Vol t6i 17vol
+Di�n ap t�i cac nhanh chia xung: 5 vol ho�c 3 vol tuy theo ghim di�n ap t�i bo 16 :8
2.2 Trinh t\l’ ki@m tra mtch tfo xung

Yeu cdu: Sic d1.mg adapter 24 Vol ti€ th11c hi?n ctic buuc kiim tra me,ch te,o xung
Khi do tli?n tip: Chinh thang do mp/chiiu tuy theo tlijn tip t{li ctic chlin, que den tl8ng h8
tl{it t{li mass (Ho(i,c tan nhiit cua 7812), quetl,itl{it te,i tli€m cin do.
-Ki@m tra ngu6n cip 24 Volvao IRF:(Ngu6n 24 Vol di qua tro: 2.2 om t6i IRF)

2,.,zJl.

-Ki@m tra ngu6ncip vao 7812: Do di�n ap tru6c va sau cua 7812
Chan 1 Chan 2 Chan 3
24Vol 0 Vol 12 Vol
Page 17

-Kiim tra ngu6n 12 Vol: Cdp vao Pin 1 cua bo xung, chan 7 cua Ic CA3140, chan C cua
transistor 8050, chan 15 cua IC t�o xung KA3525 (SG3525).
-Kiim tra chan ki�h �µa IC3525: chan s6 8 cuaic 3525 se xay ra 2 trucmg hqp
Truonghqp
1

Diin ap chan 8
5 vol
0 vol ho�c < 5vol Ghi chu
Du di�rt ap kich d8 t�o xung
Bil6i

Yeu du: Chan 8 di�n ap phai du 5 vol, nSu khong xung xudt ra chan 11 va 15 m�c du dung
di�n ap nhung vdn bi 16i xung. D�t bi�t, nSu chan 8 cua IC3525 duqc O Vol thi rridt xung
hoan toan.
NSu chan 8 chua c6 di�n ap 5Vol thi ta nen ki8m tra:

Sa d6 chan kich
+KiSm tra nhanh R2 i’, C8 xem c6 ;bi _ch�p hay khong? (�heo so d6_ tren).

+Ki8n;i tra transistor Q2 va Q3 xem c6 bi chSt hay khong?
+Thay m6i zenner ZD4 15Vol va Rl 7 780 om nSu g�p b�nhkhi han chan 8 di�n ap luc c6,
luc khong .
+N&u chan 8 vdn chua c6 5 Vol thi taOen thao tai {2 tran 8050 va 8550) sau d6 thu cdp nguf>n
l�i. Do di�n ap t�i chan 8, nSu vdn khong c6 thi thay IC3525 m6i.
Page 18

-Ki�m. tra chan phat xung:

+Truong hQ’P chan 8 da c6 5 Vol, ki�m tra chan 11 va 14 (2 chan tin hi�ll:,xung ra, di�n ap.
5vol va.tin hi�U’xung l�ch pha nhau)
+Xay ra cac truong hqp nhu sau:
Chan 11
0 Vol
5 Vol
0 Vol
<5 Vol
5 Vol

Chan 14
O Vol
o·vo1
5 Vol
<5 Vol
5 Vol

Ghi chu
·Mdt xung
;MAtxung

.Mdtxung·
Mdtxung ·
C6 xung

+Khi g{lp truong hqp mdt xung: Yeu cfiu thao bo Transistor (8050, 8550). Sau khi thaoxong,
cdp ngu6n l+NSu khong c6 5i v�l a ca 2 chan thi IC hong khi d6 ta nen thay IC 3525 m6i
+NSu c6 5 vol tsau chan · 11 va 14 nhu hinh.

. S8050
S8050

·:io.t4141
·ro,10k:C

Hirth 2 Sa d6 mPage 19

-Kiim tra tin hifu cip cho IRF:
+Di�n ap cdp va chan G cua cac IRF ldn lugt la 20 vol, 5 vol, 20 vol va 5 vol.
+Di�n ap 24 Vol c§.p cho IRF dugc thong qua :tra 2,2 om. (Nhu tren phdn ngu6n 24).
-Kiim tra x�ng tti IRF:
+Do di�n ap t�i cac IRF (Chinh thang do 50 VDC, que den d�t t�i mass, que do dijt t�i tan
nhi�t cua. cac IRF): Di�n ap do dugc t�i 4 con IRF la 13 vol t6i 17vol.tuy theo may. N6u do
dugc 24 vol ho�c OVol thi dang mdt xung.
+D6i v6i may tig/cut: Khi chua kich co di�n ap t�i IRF do duqc 24·vol, khi kich co di�n ap
t\ltxu6ng 13 vol. N6u di�n ap khong giam la dang bi mdt xung(Hongxung hoijc m�ch diSu
khiSn kich va6 chan 8 cua 3525).

-Kiim tra difn ap tti ho chia xung:

+Do n9itr6 t�i A1A2, B1B2, C1C2, D1D2: DS thang do xlO om, do l¼n lugt vao cac nh{mh
kim 16n 1 chiSu, ho�c len 2 chiSu khac nhau nhiSu, kem theo do 2 chan CE cua so kim len 1
chiSu thi Mo�fet s6ng, nguqc l�i thi so· nhanh d6 ch6t hoijc vung chia xung nhanh d6 bi 16i
cdn phai sua l�i bo chia xung.

Page 20

. +Di�n ap do t�i A1A2, B1B2, C1C2, ,D1D2 la 5 vol ho�c 3 vol. Khic6 b!t ky nhanh nao
di�n ap khac thi bit bu(>c phai sua l�i. bo cbiia xung.

-Yeu ciu trtro-c · khi cim ngu6n 220 vol xoay chi@u:
+Ciim adapter 24Vol thu xung, do xung c6 t�i irf va xung c6 t�i cac nhanh cua bo chia xung
16:8.
+Neu so bi nf>, phai ki�m tra va sua xung: KiSm tra ldn.lugt l�i cac bu6c tu kic,h xung (chan
_ 8), phat xung (chan 11 va 14), xung t�i IRF- (1’3 Vol t_�i tai nhi�t IRF), xung t�i cac nhanh
kich So (Bo chia xung 16:8).
2.3 Vung di@u chinh dong-Nhiim V\l:Vung nay duqc thgc hi�n bAng each t�o di�n ap duqc di8u chinh tu chiet ap
chinh dong gui tin hi�u vS Ca3 140 va_ d6ng thai tin hi�u tu di�n tra shunt v8 se so sanh v6i
tin hi_�u chiet ap v8 dS dua tin hi�u ve chan 2 va 9 cua KA3525 d� di8u khi�n d(> r(mg xung,
sao cho muc d�t dong han va dong thgc t8 se duqc an kh6p v6i nhau.

-Ghi chu; Yung nay se lien quan t6i b�nh him yeu, han kh6e, han chAm bao 16i
x_
tra vung
‘. c h•1eJ.t ap:
,
-Kiem

+Nguyen ly:
Ngu6n 12v- Tran 8050,tra va zen8,2 -c- Chiet ap- Vi chinh � Pin6 (bo d\mg 3525)- tra
6″.8k- chan 2 (CA3140).
Page 21

Di�n tr6 Shunt- pin4-tr6 tOOR va lk �chan 2 (CA3140).

Tin hi�u ra chan 6 (ca3140) h6i tiSp tu shunt, dua vimg xu ly dS c�p cho chan di�u khiSn
d() r()ng xung t�i IC KA3525 (Di�n �p do duqc t�i chan 6 nho hon-0,05 Vol.
+Di�n ap cdp v:ao chiSt ap d�t 7 Vol (di�n ap nay duqc ldy tu chan ngu6n 12Vol thong qua
m�ch di�u chinh transistor 8050). NSukhong d�t 7 Vol cdn kiSm tra tr6 h�n dong tu12vol,
tran 8050, tr6 phan ap cho tran 8050. Do di�n ap t�i chan 1 v� 3 cua Ric cftm chiSt ap se
duqc 7 Vol.·
Ph§.� nay yeu c§.u nguai h9c do them m�ch dS tang kinh nghi�m: Di�n ap se c6 t�i chan C
cua S8050, khi chan B �6 di�n ap se ma I phdn di�n ap tu chan C qua chan E, Chan E duqc
n6i vai di�n ap vao cua chiSt _ap.
‘

‘

+KiSm tra di�n ap ra t�i chan giua cua chiSt ap (Chinh chiSt ap phai chinh duqc di?n ap ra tu
Ov t6i 7v). (Que den vao mass, que do vao chan ‘gifra cua chiSt ap).

Page 22

+KiSm tra di�n ap t�i Pin6 cua bo dvi;lg 3525 (Khi chinh chi�t ap thi pi� 6 d�t di�n ap tir 0v
t&i 3v).

+KiSm tra chan 2 cua Ca3140 d�t di�n ap tir 0.25 t6i.0.6v khi chinh chi�t ap.
+KiSm tr� chan 6 cua Ca3140 phai d�� di�n ap d.tnh6, xip xi b�ng 0v.

Di�n ap (Vol)

Chan 2
Channgu6n Pin 6
chi�t ap
bo xung Ca3140
· 0v�3v. 0.25v;.O,.7v
7v

Chan 6.
Ca3140
<0_.05v -Cac thong sA linh kifn theo hinh drroi: _____ ———-t”
___J
…..___.
Dien ap chi et ap
v·e bo d1,mg3525

(i

�

3525

shuntve
Phan 1h01 ap ve

C

-KiJm tra lizn lu()’t eek mue di¢n ap tgi eek tJiJm eizn do.
-Niu tliJm nao khae thong s6, eizn kdm tra tli¢n ap vao, linh ki¢n lien quan.
-C6 2 t/jnh huang khi XU’ ly
+ Mu6n tang ap phia sau thi phai hg tra t/{iu vao ho(le tang ap adu vao va ngli()’e lqi.
Vi d\t: Pin6 cua ho xung 3525 khong duqc 3 vol khi chinh max chi�t ap
Cach thvc hiin:
Page 23

-Cach 1: Tang di�n ap vao chan chiSt ap (Ddu tit chan CE cua S8050, chi danh cho may que)
-Cach 2: Giam di�n tra vi chinh (B&ng each vijn num chinh,dS h� tra)
-Cach 3: Giam di�n tra 3K tru6c khi di vao Pin6 .
Phdn nay yeu cdu nguai h9c thay thu linh ki�n (Tang gia tri tra, giam gia tri tra dS d�t duqc
· di�n ap mong mubn ..
Luu y-: M(:>t s6 dong San xudt SO’ d6 m�ch�c6 thS khac; linh ki�n c6 thS khac nhung cac mire
. di�n ap t�i· C �C chan 6 cua bo hung 3525 Va. ap t�i chan 2 cua 3140 thi khong d6i (c6 th� 1 �ch
m(:>t chut nhung kh�ng nhi�u, tdm 0,2 vol).
2.4 Vong bao vf qua dong·
-Tin hifu xfrly sau biSn ap 300:1

Bo xung3525

-Nguyenly: BiSn ap 300:1 la biSnap dung dS phan h6i dSbao V�- Cu(:>n c6 1 vong duqc ddu

n6i tiSp v6i ngu6n am (cua 31 0V), nbrtnrc tiSp v6i cong sudt (So). Khi so ho�t d(:>ng thi se.
c6 dong ch�y.qua cu(:>n ‘1 vong (BiSn ap 300: 1) se duqc cam ung sang CUQll 300 vong (biSn
ap 300:1). Sau khi c6 hi�n tuqng cam ung thi se si_nh ra di�n ap tren 2 ddu cua cu(:>n 300
. vong, Di�n ap nay se duqc chinh luu thanh di�n ap 1 chi€u ( qua 1 diot 4148 ho�c qua 4 diot
4148), di�n ap 1 chi�u nay se ,di qua m�ch phan ap di�n trfr va dua vao chan 11 �ua bo xung
3525.

Page 24

• a ; .. r., ,, “. · ·. ·. · BUA CHUA MAY HAN sU ‘, ouNGCONG NGHE • INVERTERMOFET � IGBT – Cd • � � ! • • 1, , ‘ rHANG 10-2017 1 ‘ .. · ·. · PHAN I : MAY HAN DI ¥ N TU HAN QUE, TIG ; CUT PLASMACH � Y MOSFET.NGUYEN LY CO BAN-Mayhan di � n tu sir d1 ; mg cong ngh � inverter. Cong ngh � inverter sir d1 = 1 ng cong sudt d8diSu chinh dong t � i ngo ra, khac hoan toah so v6i cong ngh � SU d1 = 1 ng bi8n ap ( Su d1 = 1ng.trgc ti8p t � i CUQn thu cdp CUa bi8n ap ). – Thanh phfrn cua mayhan bao g6m : – Phfrn ngu6n tu 220VAC t � o ra di � n ap 31 OVDC, duqc cung cdp cho dan cong su và t Mosfet, clan nayduqc dong ma ph1 = 1 thudiSu khi8n xung, tin hi � u sau cong su � t duqc dua vao bi8n ap lgc d8 t � o ra muc di � n. apsau cudi � n ap 1 chiSu va duqc gful · trgc ti8p vao 2 CQC han. · – Mayhan di � n tir sir d \ lflg 3 bo m � ch – : Bo m � ch ngu6n, Bo m � ch cong sufit va Bo lgc. cAc BUOC KIEM TRA ca BAN-Bmrc 1 : Ki @ m tra phich cim – ( Day dful, phich cim, tr6 m6i, … ). + Chinh d6ng h6 vS thang do xl O ( Thang do di � n tr6 ). + Dua 2 dfru. que do vao 2 chan cua phich cim. + B � t cong tic va quan sat d6ng h6 th và y kim len l chut, d6ng nghTa phfrn nayda d � t. + NSu kim ‘ khong len : Ki8mtra day dful bi dut haykhong, cong tic ngu6n c6 hong khong, NTC ho � c PTC c6 ch8t khong, duong m � ch bi dut haykhong. + NSu kim len h8t : Ki8m tra Di6t cfru. – Bmrc 2 : Ki8m tra 2 dfru CQC han. + Chinh d6ng h6 vS thang do xl O ( Thang do di � ntr6 ) ‘ tPage 1 + Dua2 ddu · quedo vao 2 chan cua CQC han va dao chiSu quedo + Kim d6ng h6 len 1 chiSu ho � c len 2 chiSu hoa11 toan khac nhau thi phdn nay dad � t ( DanDi và chinh luu khong bi · ch � p ). + NSu kim len 2 chiSu nhu nhau cdn ki8m tra xem c6 linh ki � n bi chay nao khong ( T � i bo1 \ rc ) ,. _cac CQC bit 96 bi ch � m VO hay khong, dan Di6t D92-02. – Bmrc3 : Ki � m tra Cong. suit + Chinhd6ng h6 vS thang � o xl O ( Thangdo di � n tr và ). + Ki / in tra 2 chlin D va Scua so : … • Que do · dua vao · Chan D, que – · dendua vao chan S : Kimd6ng h6 Jen ; Queden duavao chan D ,. quedodua vao chan S : Kim d6ng h6 khong lenk8t lu � DS cua sokhong ch8t … • Cdn ki8m tra. DS cua cac so ( So duqc chia lam 4 nhanh, do v � y ch ( mg ta cdn ki8mtra h8t ca 4 nhanh ). + Ki € m. ‘ tra 2 chlin G va S cua. so : • Quedodua vao chan S, que den dua vao chan G : Kim len, Queden dua vao chanS, quedodua vao chan G kim len l chut ho � c khong len, k8t lu � n GS cua so khongchst. • M � o : C6 th8 dotrvc ti8p t ? i bo. chia xung. Bo chia iung chia thanh 4 nhanh, ki8mtra tung nhanh m9t ( Que do ben � goai, queden bemtrong thi kimd6ng h6len. Nguqc l � i kim le ; n 1 · chut ho � c khong len, K8t lu � n nhanhd6 d � t. Nhanh nao makitµ len h8t, ho � c khong len chung ta cdn ki8m tra so va nhanh cua ho chia xung. – 1P age 2P age3Bo 11 gu6nPage4l_BolµcC \ Page5f ‘ AN220VSWllCM … Su ttJ khai mtiy ! ig, cut va cac rite ciim / 1P age6I. Mica NGUONMayhan que, tig, cut cfin c6 cac di � n ap sau : – Di � n ap 220 VAC cdp dS, nuoi qu � t, t � i di � n ap 310 VDC b � ng each chinh luu d. u va tv l9cnguon. – Di � n ap 310 VDC cfip dS t � o nguf > n 24 VDC va cfip di � n tnJC tiSp cho So. – Di � n ap 24 Vol d8 dong ma Role nguf > n, cdp nguf > n cho IRF va cdp nguf > n cho 7812 va 7805. – Di � n ap 12 Vol dugc su dvng cho m � cl diSu khiSn vii t � o xuµg. : · – Di � n ap 7 Vol cfip cho chiSt ap-Di � n ap 5 vol dugc cdp dS nuoi man hinh led hiSn : thi dong. Page 71.1 Mach tao. • 310VDCJU. :. ff – � 1-1 ik � ; !, 1V .. �. :. V : – :. tlJ \ : ‘ M. ‘. XI ‘. ! 20V / 50H li > I ) NM ! HIV !, > I – = i -, :, tN, : t ‘. f ) – 1 c � • ,. -., UX5 ! ill ) ; iC ; – ! 5 l1 ! 2 \ ‘., M � ch nguyen ly ngu6n 310VACD ien ap 220 VAC ; V6i mfch ngu6n sfr d \ mg 1 ciu diot : · 1 chan 220 ” ‘ se di tr \ Jc tiSp vao 1 chan xoay chiSu, 1 chancon l � i se di qu � nhanh Ptc ho � c Ntc ds · cftp vao chan xoay chiSu con l � i cua m � ch c §. u. V6i mfch ngu6n sir d \ lng 2 diot ciu : 1 chan 220 ” ‘ se di tr \ JC ti6p vao 2 chan xoay chiSu cua 1 diot c §. u, chan cori l � i se di qua nhanh ptc ho � c ntc dS cftp cho 2 chan xoay chiSu cua diot c §. ucon l � i. – Sau khi 220 xoay chiSu duqc cdp vao diot cdu, se t � o ra duqc di � n ap 1 chiSu ( Xem l � i ( mg · dvng cua diot du ), di � n ap 1 chiSu nay duqc l9c qua tv ngu6n t � o ph � ng d � t � o ra di � n ap31 0VDC Sau d6 se c6 1 m � ch ngu6n ti r 31 0VDC t � o ra 24VDC dS cftp cho role ngu6n dS d6 � gtr \ Jc tiSp 1 chan 220 VAC ( nhanh vira di qua ptc ho � c ntc ) dS duy tri ( ptc ho � c ntc chi mo thaidiSm d §. u sau khi ddn di � n qua n6 se n6ng len va ng � t khong cho di � n di qua va da duqc duy trib � ng tiSp dism. cua role ngubn ) .. 9P age 8 cAu E > IOTNGUON24VDCNGUON310VDCTV NGUON470uF / 400VB o ngu6n may han queMa vitCaoap2. 5 s / 5 sBo ngu6n may tig / quePage9Cacpan benhthuong xay ra v6i vimg ngu6n 310 VDC : Pan 1 : Khong co ilijn_apvao 220AC ( Qugt khong 9 uay ). – KiSm tra day ddn, kiSm tra cong tic, kiSm tra nhanh ntc ( g6m ntc ; cfiu chi. . J bing each dothong day va ti € p di € in corig tic, do ntc thong. – KiSm tra qu � t ( thir cim tqrc ti € p 2 ch.an qu � t vao ngu6n 200VAC ). Pan 2 : Co 220AC ( q’u { lt co quay ) nhung chua co 310VDC. – Rut ric 310 v vao congsuftt dS tach tai cua ngu6n 310 v. – KiSm tra chan cua diot cfiu, ric cdm. – KiSm tra cfiu diot. – KiSm tra duong m � ch ( th � ong.bi dm ) �. Pan 3 : Cdm nguJn co tiing nJ to ; nhay Attomat. – KiSm tra diot cfiu, tv ngu6n, cong sud tPan 4 : Co nguJn 31OVDC nhung ch { ly i luc thi bi ngdt. . – KiSm tra ngu6n 24VDC .. :. KiSm tra dien ap cdp vao CUQn hut cua role. 24V oL – KiSm tra ti € p diSm cua role ngu6ri. Mfo stra vimg ; ngu6n : · – KiSm tra nhanh : Dot � i 2 chanphich cim ( thang do xlO om b � t cong tic thi kim. len, tit cOngtic thikim khong len. ( day, cong tic, ntcs6ng ). – KiSm tra diot cdu. – Quansat tv ngu6ri va cac ric. Page 101.2 Difn ap 24 VOL-0UQ ‘ C l � y di � n ap tu 31 OVDC ( sau m � ch chinh luu ) – Sir d \ mg ngu6n xung d € t � o ra 24VDCV t : mw0105C105C103 ! ! ) lffiWI, / .. R210. S10l ” ll # R2135100 : ! HOOC10zr ; 1-102 IN’J / R : 21 ‘. ¼t ! iJ, ; tR2070108tN41 � 109P age 11 ‘ iLinh ki � n str d1_mg : – BiSn ap xung 200 : 6 – So cong sudt ( K3878, K2611, K4107 … ) – Tram6i SIOK-T \ l va diot d � p xung cho So. – M � ch t � o xung va xu ly h6i tiSpCac bU ‘ và c ki � m tra va sfra mJch ngu6n 24V ol : – KiSm tra c6 31OVDC – Tach tai vao 7812 va IRFPage 12 – Kiem tra So, tra m6i, d � p xung-Kiem tra vimg t � o xung va XU ly h6i tiSp-Kiem tra biSn ap xung1. 3 Mfch nguon 12 Vol ‘ :: i \ _. 1 N ‘ 4002LM 7812 IC with heat sink +. 24VDC fl12VDC1. 5A. – KiSm tra ngu6n vao 24 Vol-KiSm tra chdn ra t � i 7812, dS y trucrnghgp 7812 bj, n6ng nen’kiem tra tai bi ch � p ( Thucrng thiIC cung n6ng theo, dn thay IC m6 ‘ i ) – Ngu6n 12 Vol cfip cho IC so sanh, IC dao d9ng, Transistor 8050 … Page 13Y ung khoanh tron la IC 7812, chan 1 la ngu6n cdp 24 v, chan 2 la mass, chan 3 la ngo ra 12 v. Luu y : Khi sua chung ta dn d � y t6. i ngu6n cdp, ic t � o di � n ap chudn va tai phia sau ngu6n cdp. cts dua ra nhung phan doan, m9t s6 truang hqp dn thay thu ct � rut kinh nghi � m khi sua chua. 1.4 M, ch n � uAn ‘ 5 Vol ‘ – Ki � m tra ngu6n cdp, duqc SU dl ) ng tu ngu6n 24 v ghep qua di � n tra 22 om / 3 w. · · – KiSm tra led hiSrt thi dong va kiSm. tra 7805. Page 14II. MACH TAO XUNG ; ‘ INl. l ,. _i_, _ ‘ f ‘ 1N t, ; 5 ‘ – { i � – ‘. 1. rJ / ‘ 1. ( o /. V2RUlf. �. x. – · flNl \ f – * – + t. ::: > – ‘ ! – 1 — £ f1 �, iSa d6 nguyen ‘ ly m � ch bo d \ 1 ‘ 11 g 35252.1 Nguyen ly hoJt dqng-M � ch t � o xung duqc xu ly b � ng IC t � o xung Ka3525 v6i chan ngu6n cdp la chan 15 va · chan12 ( Nhu hinh ), chan kich dS t � o duqc xung la chan s6 8, chan 2 va chan 9 la chan nh � n tinhi � u tu m � ch xu ly kich. dong va phan h6i dong vs d8 cho phep xung ma vai ddua tin hi � u xung ra de dong macho cong sudt ( So ), xung ra duqc xudt phat tµ chan 11 va14 cua IC. Tin hi � u xung nay dugc xu ly qua vung m � ch 8050 va 8550, sau do tin hi � u dugcdua qua IRF. z24 va 9 z24, tin hi � u sau IRF se duqc gui t6i m � ch chia xung 16 : 8 d � cdp choso. Bo xung 16 : 8 ho � t d-M � chxu ly chinh dong va bao dong vs tu shunt se dugc xu ly qua ic CA3140 ( le _khuSchd � i thu � t toan ). – M � ch bao v � qua dong se nh � n tin hi � u tu bi � n ap bao v � 300 : 1 dugc bao tin hi � u di � n ap vSlinh ki � n bao v � fhyrist � r ; ‘ bc Rul0v0 … ) di \ ng � txung vit d6ng thai bao 16 i qua tai 0. C ( overcircuit ). � / :. Page 15T r6t1KBo m � ch 3525 � Tieu chuin : • ,. ·, 1 : ( ,. ;. + IC3525Chan 1512 VolChan 120 VolChan8. Chan 11 · 5 Vol5 VolChan 145V ol + Chan G t � i IRF : 5 vol – 20 vol – 5 vol – 20 vol ( bao g6m 4 chan IRFZ24 va IRF9Z24 ) + Di � n ap t � i tai nhi � t cac IRF : 13 Vol t6i 17 vol + Di � n ap t � i cac nhanh chia xung : 5 vol ho � c 3 vol tuy theo ghim di � n ap t � i bo 16 : 82.2 Trinh t \ l ‘ ki @ m tra mtch tfo xungYeu cdu : Sic d1.mg adapter 24 Vol ti € th11c hi ? n ctic buuc kiim tra me, ch te, o xungKhi do tli ? n tip : Chinh thang do mp / chiiu tuy theo tlijn tip t { li ctic chlin, que den tl8ng h8tl { it t { li mass ( Ho ( i, c tan nhiit cua 7812 ), quetl, itl { it te, i tli € m cin do. – Ki @ m tra ngu6n cip 24 Volvao IRF : ( Ngu6n 24 Vol di qua tro : 2.2 om t6i IRF ) 2 ,., zJl. – Ki @ m tra ngu6ncip vao 7812 : Do di � n ap tru6c va sau cua 7812C han 1 Chan 2 Chan 324V ol 0 Vol 12 VolPage 17 – Kiim tra ngu6n 12 Vol : Cdp vao Pin 1 cua bo xung, chan 7 cua Ic CA3140, chan C cuatransistor 8050, chan 15 cua IC t � o xung KA3525 ( SG3525 ). – Kiim tra chan ki � h � µa IC3525 : chan s6 8 cuaic 3525 se xay ra 2 trucmg hqpTruonghqpDiin ap chan 85 vol0 vol ho � c < 5 volGhi chuDu di � rt ap kich d8 t � o xungBil6iYeu du : Chan 8 di � n ap phai du 5 vol, nSu khong xung xudt ra chan 11 va 15 m � c du dungdi � n ap nhung vdn bi 16 i xung. D � t bi � t, nSu chan 8 cua IC3525 duqc O Vol thi rridt xunghoan toan. NSu chan 8 chua c6 di � n ap 5V ol thi ta nen ki8m tra : Sa d6 chan kich + KiSm tra nhanh R2 i ', C8 xem c6 ; bi _ch � p hay khong ? ( � heo so d6_ tren ). + Ki8n ; i tra transistor Q2 va Q3 xem c6 bi chSt hay khong ? + Thay m6i zenner ZD4 15V ol va Rl 7 780 om nSu g � p b � nhkhi han chan 8 di � n ap luc c6, luc khong. + N và u chan 8 vdn chua c6 5 Vol thi taOen thao tai { 2 tran 8050 va 8550 ) sau d6 thu cdp nguf > nl � i. Do di � n ap t � i chan 8, nSu vdn khong c6 thi thay IC3525 m6i. Page 18 – Ki � m. tra chan phat xung : + Truong hQ’P chan 8 da c6 5 Vol, ki � m tra chan 11 va 14 ( 2 chan tin hi � ll :, xung ra, di � n ap. 5 vol va.tin hi � U’xung l � ch pha nhau ) + Xay ra cac truong hqp nhu sau : Chan 110 Vol5 Vol0 Vol < 5 Vol5 VolChan 14O Volo · vo15 Vol < 5 Vol5 VolGhi chu · Mdt xung ; MAtxung. Mdtxung · Mdtxung · C6 xung + Khi g { lp truong hqp mdt xung : Yeu cfiu thao bo Transistor ( 8050, 8550 ). Sau khi thaoxong, cdp ngu6n l + NSu khong c6 5 i v � l a ca 2 chan thi IC hong khi d6 ta nen thay IC 3525 m6i + NSu c6 5 vol tsau chan · 11 va 14 nhu hinh .. S8050S8050 · : io. t4141 · ro, 10 k : CHirth 2 Sa d6 mPage 19 - Kiim tra tin hifu cip cho IRF : + Di � n ap cdp va chan G cua cac IRF ldn lugt la 20 vol, 5 vol, 20 vol va 5 vol. + Di � n ap 24 Vol c §. p cho IRF dugc thong qua : tra 2,2 om. ( Nhu tren phdn ngu6n 24 ). - Kiim tra x � ng tti IRF : + Do di � n ap t � i cac IRF ( Chinh thang do 50 VDC, que den d � t t � i mass, que do dijt t � i tannhi � t cua. cac IRF ) : Di � n ap do dugc t � i 4 con IRF la 13 vol t6i 17vol.tuy theo may. N6u dodugc 24 vol ho � c OVol thi dang mdt xung. + D6i v6i may tig / cut : Khi chua kich co di � n ap t � i IRF do duqc 24 · vol, khi kich co di � n apt \ ltxu6ng 13 vol. N6u di � n ap khong giam la dang bi mdt xung ( Hongxung hoijc m � ch diSukhiSn kich va6 chan 8 cua 3525 ). - Kiim tra difn ap tti ho chia xung : + Do n9itr6 t � i A1A2, B1B2, C1C2, D1D2 : DS thang do xlO om, do l¼n lugt vao cac nh { mhkim 16 n 1 chiSu, ho � c len 2 chiSu khac nhau nhiSu, kem theo do 2 chan CE cua so kim len 1 chiSu thi Mo � fet s6ng, nguqc l � i thi so · nhanh d6 ch6t hoijc vung chia xung nhanh d6 bi 16 icdn phai sua l � i bo chia xung. Page 20. + Di � n ap do t � i A1A2, B1B2, C1C2, , D1D2 la 5 vol ho � c 3 vol. Khic6 b ! t ky nhanh naodi � n ap khac thi bit bu ( > c phai sua l � i. bo cbiia xung. – Yeu ciu trtro-c · khi cim ngu6n 220 vol xoay chi @ u : + Ciim adapter 24V ol thu xung, do xung c6 t � i irf va xung c6 t � i cac nhanh cua bo chia xung16 : 8. + Neu so bi nf >, phai ki � m tra va sua xung : KiSm tra ldn.lugt l � i cac bu6c tu kic, h xung ( chan_ 8 ), phat xung ( chan 11 va 14 ), xung t � i IRF – ( 1 ‘ 3 Vol t_ � i tai nhi � t IRF ), xung t � i cac nhanhkich So ( Bo chia xung 16 : 8 ). 2.3 Vung di @ u chinh dong-Nhiim V \ l : Vung nay duqc thgc hi � n bAng each t � o di � n ap duqc di8u chinh tu chiet apchinh dong gui tin hi � u vS Ca3 140 va_ d6ng thai tin hi � u tu di � n tra shunt v8 se so sanh v6itin hi_ � u chiet ap v8 dS dua tin hi � u ve chan 2 va 9 cua KA3525 d � di8u khi � n d ( > r ( mg xung, sao cho muc d � t dong han va dong thgc t8 se duqc an kh6p v6i nhau. – Ghi chu ; Yung nay se lien quan t6i b � nh him yeu, han kh6e, han chAm bao 16 ix_tra vung ‘. c h • 1 eJ. t ap : – Kiem + Nguyen ly : Ngu6n 12 v – Tran 8050, tra va zen8, 2 – c – Chiet ap – Vi chinh � Pin6 ( bo d \ mg 3525 ) – tra6 “. 8 k – chan 2 ( CA3140 ). Page 21D i � n tr6 Shunt – pin4-tr6 tOOR va lk � chan 2 ( CA3140 ). Tin hi � u ra chan 6 ( ca3140 ) h6i tiSp tu shunt, dua vimg xu ly dS c � p cho chan di � u khiSnd ( ) r ( ) ng xung t � i IC KA3525 ( Di � n � p do duqc t � i chan 6 nho hon-0, 05 Vol. + Di � n ap cdp v : ao chiSt ap d � t 7 Vol ( di � n ap nay duqc ldy tu chan ngu6n 12V ol thong quam � ch di � u chinh transistor 8050 ). NSukhong d � t 7 Vol cdn kiSm tra tr6 h � n dong tu12vol, tran 8050, tr6 phan ap cho tran 8050. Do di � n ap t � i chan 1 v � 3 cua Ric cftm chiSt ap seduqc 7 Vol. · Ph §. � nay yeu c §. u nguai h9c do them m � ch dS tang kinh nghi � m : Di � n ap se c6 t � i chan Ccua S8050, khi chan B � 6 di � n ap se ma I phdn di � n ap tu chan C qua chan E, Chan E duqcn6i vai di � n ap vao cua chiSt _ap. + KiSm tra di � n ap ra t � i chan giua cua chiSt ap ( Chinh chiSt ap phai chinh duqc di ? n ap ra tuOv t6i 7 v ). ( Que den vao mass, que do vao chan ‘ gifra cua chiSt ap ). Page 22 + KiSm tra di � n ap t � i Pin6 cua bo dvi ; lg 3525 ( Khi chinh chi � t ap thi pi � 6 d � t di � n ap tir 0 vt và i 3 v ). + KiSm tra chan 2 cua Ca3140 d � t di � n ap tir 0.25 t6i. 0.6 v khi chinh chi � t ap. + KiSm tr � chan 6 cua Ca3140 phai d � � di � n ap d. tnh6, xip xi b � ng 0 v. Di � n ap ( Vol ) Chan 2C hanngu6n Pin 6 chi � t apbo xung Ca3140 · 0 v � 3 v. 0.25 v ;. O ,. 7 v7vChan 6. Ca3140 < 0 _. 05 v - Cac thong sA linh kifn theo hinh drroi : _____----------t " ___J ..... ___. Dien ap chi et apv · e bo d1, mg3525 ( i3525shuntvePhan 1 h01 ap ve-KiJm tra lizn lu ( ) ' t eek mue di ¢ n ap tgi eek tJiJm eizn do. - Niu tliJm nao khae thong s6, eizn kdm tra tli ¢ n ap vao, linh ki ¢ n lien quan. - C6 2 t / jnh huang khi XU ' ly + Mu6n tang ap phia sau thi phai hg tra t / { iu vao ho ( le tang ap adu vao va ngli ( ) ' e lqi. Vi d \ t : Pin6 cua ho xung 3525 khong duqc 3 vol khi chinh max chi � t apCach thvc hiin : Page 23 - Cach 1 : Tang di � n ap vao chan chiSt ap ( Ddu tit chan CE cua S8050, chi danh cho may que ) - Cach 2 : Giam di � n tra vi chinh ( B và ng each vijn num chinh, dS h � tra ) - Cach 3 : Giam di � n tra 3K tru6c khi di vao Pin6. Phdn nay yeu cdu nguai h9c thay thu linh ki � n ( Tang gia tri tra, giam gia tri tra dS d � t duqc · di � n ap mong mubn .. Luu y - : M ( : > t s6 dong San xudt SO ‘ d6 m � ch � c6 thS khac ; linh ki � n c6 thS khac nhung cac mire. di � n ap t � i · C � C chan 6 cua bo hung 3525 Va. ap t � i chan 2 cua 3140 thi khong d6i ( c6 th � 1 � chm ( : > t chut nhung kh � ng nhi � u, tdm 0,2 vol ). 2.4 Vong bao vf qua dong · – Tin hifu xfrly sau biSn ap 300 : 1B o xung3525-Nguyenly : BiSn ap 300 : 1 la biSnap dung dS phan h6i dSbao V � – Cu ( : > n c6 1 vong duqc ddun6i tiSp v6i ngu6n am ( cua 31 0V ), nbrtnrc tiSp v6i cong sudt ( So ). Khi so ho � t d ( : > ng thi se. c6 dong ch � y.qua cu ( : > n ‘ 1 vong ( BiSn ap 300 : 1 ) se duqc cam ung sang CUQll 300 vong ( biSnap 300 : 1 ). Sau khi c6 hi � n tuqng cam ung thi se si_nh ra di � n ap tren 2 ddu cua cu ( : > n 300. vong, Di � n ap nay se duqc chinh luu thanh di � n ap 1 chi € u ( qua 1 diot 4148 ho � c qua 4 diot4148 ), di � n ap 1 chi � u nay se, di qua m � ch phan ap di � n trfr va dua vao chan 11 � ua bo xung3525. Page 24

Source: https://dichvubachkhoa.vn
Category: Dịch Vụ Sửa Chữa